1. Reference problem

1.1. Geometry

We consider two cubes \(A\) and \(B\) with side \(a\mathrm{=}2\mathit{mmm}\). The two cubes are initially in contact (no step between \(A\) and \(B\)).

Here is the position of the reference points (\(\mathit{mm}\)):

Cube	Point	\(x\)	\(y\)	\(z\)
\(A\)	\(\mathit{NH1}\)	2	0	2
\(A\)	\(\mathit{NH2}\)	2	2	2	2
\(A\)	\(\mathit{NH3}\)	0	2	2
\(A\)	\(\mathit{NH4}\)	0	0	2
\(A\)	\(\mathit{NH5}\)	2	0	4
\(A\)	\(\mathit{NH6}\)	2	2	4
\(A\)	\(\mathit{NH7}\)	0	0	2	4
\(A\)	\(\mathit{NH8}\)	0	0	4
\(A\)	\(\mathit{NH9}\)	2	2	1	2
\(A\)	\(\mathit{NH10}\)	1	2	2
\(A\)	\(\mathit{NH11}\)	0	1	2
\(A\)	\(\mathit{NH12}\)	1	0	2
\(A\)	\(\mathit{NH17}\)	2	2	1	4
\(A\)	\(\mathit{NH18}\)	1	2	4
\(A\)	\(\mathit{NH19}\)	0	0	1	4
\(A\)	\(\mathit{NH20}\)	1	0	4
\(A\)	\(\mathit{NH26}\)	1	1	4
\(A\)	\(\mathit{NH21}\)	1	1	2
\(B\)	\(\mathit{NB1}\)	2	0	0
\(B\)	\(\mathit{NB2}\)	2	2	0
\(B\)	\(\mathit{NB3}\)	0	0	2	0
\(B\)	\(\mathit{NB4}\)	0	0	0
\(B\)	\(\mathit{NB5}\)	2	0	2
\(B\)	\(\mathit{NB6}\)	2	2	2	2
\(B\)	\(\mathit{NB7}\)	0	2	2
\(B\)	\(\mathit{NB8}\)	0	0	2
\(B\)	\(\mathit{NB17}\)	2	2	1	2
\(B\)	\(\mathit{NB18}\)	1	2	2	2
\(B\)	\(\mathit{NB19}\)	0	1	2
\(B\)	\(\mathit{NB20}\)	1	0	2
\(B\)	\(\mathit{NB26}\)	1	1	2
\(B\)	\(\mathit{NB9}\)	2	2	1	0
\(B\)	\(\mathit{NB10}\)	1	2	0
\(B\)	\(\mathit{NB11}\)	0	0	1	0
\(B\)	\(\mathit{NB12}\)	1	0	0
\(B\)	\(\mathit{NB21}\)	1	1	0

1.2. Material properties

The two cubes are elastic with:

• Poisson’s ratio: \(0\)

• Young’s module: \(200\mathit{GPa}\)

1.3. Boundary conditions and loads

We impose a \(\mathit{DZ}\mathrm{=}\mathrm{-}\mathrm{0.2mm}\) displacement on the \(A\) cube. The two cubes are in contact without friction.