3. Modeling A#

Modeling A is the reference calculation, based on elastoplastic modeling (isotropic work hardening model with bi-linear tension curve) in axisymmetric massive finite elements. The calculated quantities depend only on the radial direction. The three tubes (with their three different thickness/radius ratios) are calculated together.

3.1. Characteristics of the mesh#

The quadratic mesh is very refined: 100 mesh QUAD8 in thickness, but one mesh along the axis of the tube. There are 503 knots.

3.2. Characteristics of nonlinear static modeling and loading conditions#

Solid finite elements are axisymmetric. The length of the modelled tubes is \(10 \mathit{mm}\). The lower face is affected by total blocking in the axial direction; the upper face is affected by a uniform connection in the axial direction in order to simulate kinematics identical to that of a very long tube. The time step chosen is \(0.5\), fixed for all non-linear calculation steps; however, a cut is authorized in case of convergence failure, the criterion « RESI_GLOB_RELA » being set to \(10^{-6}\). Newton’s method uses the option « MATRICE =” TANGENTE “``. (To draw the curves, we use a calculation carried out with a maximum time step of \(0.1\).)

The pressures are respectively applied to the inner and outer edges. To calculate the limit pressure (path 2), load control is used by controlling the load by the radial movement of a node in the external wall.

3.3. Tested sizes and results#

For information, the calculated values are indicated. These values are used as reference values for other models. The tests correspond to non-regression tests, except for tangential stresses, where we compare to the average value indicated in ce tableau (The average value is not necessarily the value calculated at the level of the middle sheet, but it gives an order of magnitude).

3.3.1. Route 1#

  • Radial displacement on the mean surface (tube \(h/R = 1/20\))

DX displacement on average surface

value (m)

Instant t = 0.5

0.011902

Instant t = 1.

0.176855

Instant t = 2.

0.176007

Instant t = 3.

0.150506

Instant t = 4.

0.105688

Instant t = 5.

0.130341

  • Radial displacement on the mean surface (tube \(h/R = 1/10\))

DX displacement on average surface

value (m)

Instant t = 0.5

0.011668

Instant t = 1.

0.165026

Instant t = 2.

0.163329

Instant t = 3.

0.136599

Instant t = 4.

0.071341

Instant t = 5.

0.096374

  • Radial displacement on the mean surface (tube \(h/R = 1/5\))

DX displacement on average surface

value (m)

Instant t = 0.5

0.011158

Instant t = 1.

0.141588

Instant t = 2.

0.138094

Instant t = 3.

0.108989

Instant t = 4.

0.003604

Instant t = 5.

0.029314

  • Uniform axial displacement \(h/R = 1/20\) tube

DY displacement on average surface

value (m)

Instant t = 0.5

-0.00034568

Instant t = 1.

-0.00805735

Instant t = 2.

-0.00798468

Instant t = 3.

-0.00714781

Instant t = 4.

-0.00542527

Instant t = 5.

-0.00618936

  • Uniform axial displacement \(h/R = 1/10\) tube

DY displacement on average surface

value (m)

Instant t = 0.5

-0.00032818

Instant t = 1.

-0.00720990

Instant t = 2.

-0.00706445

Instant t = 3.

-0.00611717

Instant t = 4.

-0.00332040

Instant t = 5.

-0.00412222

  • Uniform axial displacement \(h/R = 1/5\) tube

DY displacement on average surface

value (m)

Instant t = 0.5

-0.00029454

Instant t = 1.

-0.00564851

Instant t = 2.

-0.00535760

Instant t = 3.

-0.00418669

Instant t = 4.

-0.00009860

Instant t = 5.

-0.00010608

  • Circumferential surface stress (mean tube \(h/R = 1/20\)) interpolated at the nodes of the mesh

Component SIZZ on an average area

value (MPa)

Tolerance (%)

Instant t = 0.5

195

0.1

Instant t = 1.

390

0.1

Instant t = 2.

370

0.1

Instant t = 3.

-60

0.5

Instant t = 4.

-410

0.1

Instant t = 5.

0.0

0.2 (ABSOLU)

  • Circumferential surface stress (mean tube \(h/R = 1/10\)) interpolated at the nodes of the mesh

Component SIZZ on an average area

value (MPa)

Tolerance (%)

Instant t = 0.5

190

0.5

Instant t = 1.

380

0.1

Instant t = 2.

340

0.1

Instant t = 3.

-120

0.6

Instant t = 4.

-420

0.1

Instant t = 5.

0.0

0.8 (ABSOLU)

  • Circumferential surface stress (mean tube \(h/R = 1/5\)) interpolated at the nodes of the mesh

Component SIZZ on an average area

value (MPa)

Tolerance (%)

Instant t = 0.5

180

0.6

Instant t = 1.

360

0.5

Instant t = 2.

280

0.5

Instant t = 3.

-240

1.2

Instant t = 4.

-440

0.5

Instant t = 5.

0.0

3 (ABSOLU)

  • Cumulative plastic deformation on the mean surface (tube \(h/R = 1/20\)) interpolated at the nodes of the mesh

Component V1 on average area

worthiness

Instant t = 0.5

0.0

Instant t = 1.

0.015307

Instant t = 2.

0.015307

Instant t = 3.

0.015307

Instant t = 4.

0.017576

Instant t = 5.

0.017576

  • Cumulative plastic deformation on the mean surface (tube \(h/R = 1/10\)) interpolated at the nodes of the mesh

Component V1 on average area

worthiness

Instant t = 0.5

0.0

Instant t = 1.

0.014177

Instant t = 2.

0.014177

Instant t = 3.

0.014177

Instant t = 4.

0.018703

Instant t = 5.

0.018703

  • Cumulative plastic deformation on the mean surface (tube \(h/R = 1/5\)) interpolated at the nodes of the mesh

Component V1 on average area

worthiness

Instant t = 0.5

0.0

Instant t = 1.

0.011940

Instant t = 2.

0.011940

Instant t = 3.

0.011940

Instant t = 4.

0.020925

Instant t = 5.

0.020925

3.3.2. Route 2#

  • Pressure reached for tube \(h/R = 1/20\)

Coefficient factor of the applied pressure

worthiness

Instant t = 0.5

4,201

Instant t = 1.

8,402

Instant t = 2.

16,594

Instant t = 3.

16,718

Instant t = 4.

16,722

Instant t = 5.

16,726

  • Pressure reached for tube \(h/R = 1/10\)

Coefficient factor of the applied pressure

worthiness

Instant t = 0.5

4,285

Instant t = 1.

8,570

Instant t = 2.

16,689

Instant t = 3.

16,924

Instant t = 4.

16,928

Instant t = 5.

16,932

  • Radial displacement on the mean surface (tube \(h/R = 1/5\))

Coefficient factor of the applied pressure

worthiness

Instant t = 0.5

4,480

Instant t = 1.

8,961

Instant t = 2.

16,879

Instant t = 3.

17,334

Instant t = 4.

17,339

Instant t = 5.

17,343

  • Average circumferential stress on the surface of the \(h/R = 1/20\) tube

Component SIZZ in on average area

value (MPa)

Instant t = 3.

322,26

Instant t = 5.

321.94

  • Average circumferential stress on the surface of the \(h/R = 1/10\) tube

Component SIZZ in on average area

value (MPa)

Instant t = 3.

312.97

Instant t = 5.

312.19

  • Average circumferential stress on the surface of the \(h/R = 1/5\) tube

Component SIZZ in on average area

value (MPa)

Instant t = 3.

290.33

Instant t = 5.

288,79

  • Cumulative plastic deformation on the average surface of the \(h/R = 1/20\) tube

Component V1 on average area

worthiness

Instant t = 3.

1,129E-3

Instant t = 5.

3,210E-3

  • Cumulative plastic deformation on the average surface of the \(h/R = 1/10\) tube

Component V1 on average area

worthiness

Instant t = 3.

1,281E-3

Instant t = 5.

3,457E-3

  • Cumulative plastic deformation on the average surface of the \(h/R = 1/5\) tube

Component V1 on average area

worthiness

Instant t = 3.

1,664E-3

Instant t = 5.

4,073E-3