1. Reference problem#
1.1. Geometry#
The half-ring consists of two inner and outer parts, of the same thickness \(5\mathit{mm}\). The radius of the neutral fiber is \(95\mathit{mm}\). The block is a rectangle with dimensions \(50\mathit{mm}\) by \(250\mathit{mm}\). The initial distance between the block and the half-ring is \(20\mathit{mm}\).

1.2. Material properties#
The law of behavior used is elastoplastic with linear isotropic work hardening (VMIS_ISOT_LINE).
The material of the inner part of the ring is characterized by:
\(E=100000\mathit{MPa}\)
\(\nu =0.3\)
\(\rho =2.7E-5{\mathit{kg.mm}}^{-3}\)
\(\text{D\_SIGM\_EPSI}=9.0E4\mathit{MPa}\)
\(\text{SY}=10.E100\mathit{MPa}\)
The material of the outer part of the ring is characterized by:
\(E=1000\mathit{MPa}\)
\(\nu =0.3\)
\(\rho =2.7E-5{\mathit{kg.mm}}^{-3}\)
\(\text{D\_SIGM\_EPSI}=9.0E2\mathit{MPa}\)
\(\text{SY}=10.E100\mathit{MPa}\)
The block material is characterized by:
\(E=300\mathit{MPa}\)
\(\nu =0.3\)
\(\rho =2.7E-5{\mathit{kg.mm}}^{-3}\)
\(\text{D\_SIGM\_EPSI}=10.\mathit{MPa}\)
\(\text{SY}=10.E100\mathit{MPa}\)
1.3. Boundary conditions and loads#
The bottom edge of the block is stuck such as \(\mathit{DX}=\mathit{DY}=0\).
A displacement \(\mathit{DX}=0\) and \(\mathit{DY}=-90\mathit{mm}\) is imposed at both ends, in plane \(\mathit{XZ}\), of the half-ring.
1.4. Other calculation parameters#
The calculation is done with the operator DYNA_NON_LINE. The diagram is used in time HHT (SCHEMA =” HHT “) with the parameter ALPHA to -0.3 (the default value of this parameter is -0.1 and it leads to a calculation time that is too long for modeling B).