1. Reference problem#

1.1. Geometry#

_images/Shape1.gif

Uy = 0

_images/Shape3.gif

Consider a test tube \(\mathrm{CT25}\) with a ligament length: \(a=27.5\mathrm{mm}\) (\(a/W=0.55\)). Along the \(z\) axis, the thickness is \(e=1\mathrm{mm}\). Test piece \(\mathrm{CT25}\) is modelled in plane deformations. For reasons of symmetry, one half of it is represented in \(\mathrm{2D}\).

1.2. Material properties#

Young’s modulus: 214100 \(\mathrm{Mpa}\)

Poisson’s ratio: \(\nu =0.3\). The traction curve used is shown in the following table:

\(\epsilon\)

\(\sigma (\text{MPa})\)

0.003439678

740.6632663

0.004628373

842.148772

0.00607988

876.3117064

0.007654628

895.2063119

0.010417548

911.0718694

0.014178015

925.022448

0.017543214

935.2135771

0.021942493

945.6948965

0.027416704

960.732311

0.033866984

975.8041996

0.040205805

988.2450325

0.046616375

1000.143035

0.052903597

1010.004051

0.058235889

1017.5664

Table 1.1

1.3. Boundary conditions and loads#

The load is of the displacement type imposed at a point located in the center of the pin, which is modelled by four undeformable angular sectors. With half of the test piece modelled, a symmetry condition is applied to the ligament (\(y=0\)).