3. Modeling A#
3.1. Characteristics of modeling#
TRIA3, QUAD4
For reasons of symmetry, we mesh only half the thickness of the wall. The modeling is done on a height \(H=0.1m\) with 2 layers of elements.
3.2. Characteristics of the mesh#
Number of knots: 18
Number of meshes and types: 5 QUAD4, 10 TRIA3
3.3. Tested values#
Identification |
Reference |
Aster |
% difference |
\(\mathrm{M1}(x=0.02)\mathrm{N16}\) |
|||
\(t=0.1\) |
100.00 |
99.998 |
+0.00 |
\(t=0.5\) |
99.408 |
99.042 |
—0.37 |
\(t=2.0\) |
79.859 |
79.794 |
—0.08 |
\(t=10.0\) |
15.717 |
16.138 |
+2.68 |
\(\mathrm{M2}(x=0.08)\mathrm{N6}\) |
|||
\(t=0.1\) |
93.666 |
93.380 |
—0.31 |
\(t=0.5\) |
63.500 |
63.813 |
+0.49 |
\(t=2.0\) |
35.717 |
35.667 |
—0.14 |
\(t=10.0\) |
6.7948 |
6.9326 |
+2.03 |
\(M’1(x=0.02)\mathrm{N14}\) |
|||
\(t=0.1\) |
100.00 |
99.998 |
+0.00 |
\(t=0.5\) |
99.408 |
99.077 |
—0.33 |
\(t=2.0\) |
79.859 |
80.002 |
+0.18 |
\(t=10.0\) |
15.717 |
16.211 |
+3.14 |
\(M’2(x=0.08)\mathrm{N4}\) |
|||
\(t=0.1\) |
93.666 |
92.895 |
—0.82 |
\(t=0.5\) |
63.500 |
61.882 |
—2.55 |
\(t=2.0\) |
35.717 |
35.331 |
—1.08 |
\(t=10.0\) |
6.7948 |
6.8885 |
+1.38 |