2. Benchmark solution#

2.1. Calculation method used for the reference solution#

The reference solution is an approximate analytical solution. The approximate analytical fluctuating potentials to calculate the added stiffness are written as [bib1]:

\(\mathrm{\{}\begin{array}{ccc}{\varphi }_{1}(r,\theta ,y)\mathrm{=}& \frac{{R}_{e}^{2}}{{R}_{e}^{2}\mathrm{-}{R}_{i}^{2}}(r+\frac{{R}_{i}^{2}}{r})& \mathrm{sin}\theta \mathrm{sin}\frac{\pi (y+l\mathrm{/}2)}{l}\\ {\varphi }_{2}(r,\theta ,y)\mathrm{=}& \frac{{R}_{e}^{2}}{{R}_{e}^{2}\mathrm{-}{R}_{i}^{2}}(r+\frac{{R}_{i}^{2}}{r})& \mathrm{sin}\theta \mathrm{cos}\frac{\pi (y+l\mathrm{/}2)}{l}\end{array}\)

The stiffness added to the first mode of flexure of the outer cylinder considered as a swivel and swivel beam is written [bib1]:

\({K}_{A}\mathrm{=}\mathrm{-}\frac{\rho }{2}\frac{{V}_{0}^{2}{\pi }^{3}{R}_{e}^{3}}{({R}_{e}^{2}\mathrm{-}{R}_{i}^{2})l}({R}_{e}+\frac{{R}_{i}^{2}}{{R}_{e}})\)

This stiffness, calculated on a cylindrical geometry, is then assigned to a model with an equivalent degree of freedom.

The system with an equivalent degree of freedom is an equivalent mass-spring system to which is assigned a mass equal to the mass of the system increased by the mass added by the fluid and a stiffness equal to the stiffness of the system increased by the stiffness added by the flow for various speeds.

The mass of the system in air is:

\(M\mathrm{=}10292\mathit{kg}\)

for an external cylindrical shell with a thickness:

\(C\mathrm{=}{2.10}^{\mathrm{-}3}m\)

For equivalent stiffness in air of the « outer shell » system, we take the stiffness of a beam subjected to a force distributed over its entire length:

_images/10000D66000027610000052B117D0A01DB11CF31.svg

So \(K\mathrm{=}2.533{10}^{4}N\mathrm{/}m\)

The equivalent system coupled to the flow is represented by the following diagram:

_images/1000027200000B0F0000052BB5A3FD7B4A90F759.svg

with \(m\mathrm{=}M+{M}_{A}\) \(k\mathrm{=}K+{K}_{A}\)

The natural pulsation of the coupled system evolves according to the square of the flow speed. If we call \({V}_{{0}_{C}}\) the critical flow speed for which the stiffness \(k\) is cancelled out:

\(\mathrm{\exists }{V}_{{0}_{C}},K+{K}_{A}({V}_{{0}_{C}})\mathrm{=}0\) with \({V}_{{0}_{C}}^{2}\mathrm{=}\frac{2({R}_{e}^{2}\mathrm{-}{R}_{i}^{2})lK}{({R}_{e}+\frac{{R}_{i}^{2}}{{R}_{e}})\rho {\pi }^{3}{R}_{e}^{3}}\)

so we show that:

\(\omega ({V}_{0})\mathrm{=}{\omega }_{e}(0)\sqrt{1\mathrm{-}{x}^{2}}\)

where we put:

\({\omega }_{e}(0)\mathrm{=}\sqrt{\frac{K}{M+{M}_{A}}}\) (natural pulsation of the system in fluid at rest)

\(x\mathrm{=}\frac{{V}_{0}}{{V}_{{0}_{C}}}\) (reduced flow speed)

The pulsation of the fluid at rest is equal to: \(\omega \mathrm{=}0.085\mathit{rad}\mathrm{/}s\).

2.2. Benchmark results#

The natural frequency of the system is calculated for different flow velocities.

\({V}_{0}(m\mathrm{/}s)\)

0.5

1.5

2.2

2.688

\({M}_{A}(\mathit{kg})\)

3.486E6

3.486E6

3.486E6

3.486E6

3.486E6

3.486E6

\({K}_{A}(N/m)\)

—876.5

—7888.50

—7888.50

—14023.95

—16968.98

—25330

\({M}_{\mathrm{total}}(\mathrm{kg})\)

3.491E+6

=

=

=

=

=

=

\({K}_{\mathit{total}}(N\mathrm{/}m)\)

24453.5

17441.5

17441.5

11306.05

8361.00

\(f({V}_{0})\mathrm{\times }{10}^{\mathrm{-}2}(\mathit{Hz})\)

1.318

1.112

1.112

0.896

0.772

2.3. Uncertainty about the solution#

Semi-analytical solution.

2.4. Bibliographical references#

  1. ROUSSEAU G., LUU H.T. - Mass, damping and stiffness added for a vibrating structure placed in a potential flow - Internal note EDF/DER, HP-61/95/064/A (1995).