1. Reference problem#
1.1. Geometry#
Cylinder with:
Inner radius |
\({R}_{i}=0.04m\) |
Outside radius |
\({R}_{e}=0.08m\) |
Height |
\(L=0.04m\) |
1.2. Material properties#
The material is homogeneous, isotropic, and linear thermoelastic. The mechanical properties of materials depend on temperature. The properties vary linearly between the 2 extreme temperatures: \(0°C\) and \(100°C\).
Law of behavior with linear isotropic work hardening:
Thermal properties and density:
1.3. Boundary conditions and loads#
The thermal shock is modelled by a heat flow of \(300000W/{m}^{\mathrm{2s}}\) inside the cylinder. The structure has an initial temperature of \(0°C\).
At the same time a centrifugal force is applied: over an interval of \(15s\), the rotation speed is increased to \(2400\mathrm{rad}/s\), then kept constant.
After \(15s\), internal pressure is applied: the pressure increases linearly to a value of \(5.5\mathrm{MPa}\) which is reached at \(20s\), then the pressure goes down to zero.
The thermal calculation and the mechanical calculation are carried out with 50 identical time steps.
A quarter of the cylinder is modelled by fixing the transverse components of the movements to the two transverse sections of the cylinder. In addition, the degree of translation along the length of the cylinder is fixed on the inner radius of the lower side of the cylinder.