2. Benchmark solution#

2.1. Static calculation: embedded beam#

The theory of beams working under bending provides a reference value for maximum displacement. For a beam embedded at one end and free at the other under distributed loading, the maximum displacement at the free end, called an arrow, is given by:

\(f\mathrm{=}\frac{\mathrm{-}{\mathit{qL}}^{4}}{{\mathrm{8EI}}_{\mathit{eq}}}\)

  • \(q\): the force distributed in \(N/m\).

  • \(L\): the length of the beam in \(m\).

  • \({\mathit{EI}}_{\mathit{eq}}\): in the mono-material case it is the product of the Young’s modulus and the quadratic moment.

In the multi-material case, and with the configuration described above, \({\mathit{EI}}_{\mathit{eq}}\) is calculated as follows:

\({\mathit{EI}}_{\mathit{eq}}\mathrm{=}{\mathrm{\int }}_{S}E(s){z(s)}^{2}\mathit{ds}\)

In Code_Aster this calculation is approximated by a sum on the fibers:

\({\mathit{EI}}_{\mathit{eq}}\mathrm{=}{\mathrm{\sum }}_{i\mathrm{=}1}^{{\mathit{nb}}_{\mathit{fibres}}}{E}_{i}{{z}_{i}}^{2}{A}_{i}\)

where \({z}_{i}\) is the \(Z\) coordinate of the center of the fiber \(i\) and where \({A}_{i}\) is its surface.

2.3. Uncertainties about the solution#

None.