1. Reference problem#

1.1. Geometry#

_images/100000000000015000000229479178F85E54E778.png

1.2. Material properties#

1.2.1. Material 1#

Young’s module

\(E=6\times {10}^{12}\mathit{Pa}\)

Poisson’s Ratio

\(\nu =0.2\)

1.2.2. Material 2#

Young’s module

\(E=1\times {10}^{11}\mathit{Pa}\)

Poisson’s Ratio

\(\nu =0.3\)

1.2.3. Material 3#

Young’s module

\(E=2\times {10}^{11}\mathit{Pa}\)

Poisson’s Ratio

\(\nu =0.2\)

1.3. Boundary conditions and loads#

Points \(\mathit{P8}\) and \(\mathit{P8S}\) are used to apply force \({F}_{Y}\).

The lip of the crack is line \(\mathit{P8P0}\). So \(\mathit{P0}\) is the crack front.

For all the calculations carried out, the same movements are imposed.

Imposed displacement:

Embedding on side \(\mathit{P8P9S}\)

\(\mathit{DX}=0\)

Embedding on side \(\mathit{P8SP9}\)

\(\mathit{DX}=0\)

Embedding node \(\mathit{P11}\)

\(\mathit{DY}=0\)

According to the calculations, 2 types of loading are imposed:

Imposed loading:

Pressure distributed over line \(\mathit{P0P8}\)

\(1.\)

Pressure distributed over line \(\mathit{P0P8S}\)

\(1.\)

Or:

Nodal force on the GROUP_NO \(\mathit{P8}\)

\(\mathit{Fy}=1.591549E-3\)

Nodal force on the GROUP_NO \(\mathit{P8S}\)

\(\mathit{Fy}=-1.591549E-3\)