1. Reference problem#

1.1. Geometry#

A rotor model supported by 2 bearings (nodes \(\mathrm{B1}\) and \(\mathrm{B2}\) in the figure below), whose stiffness and damping matrices are non-symmetric. It is composed of 3 discs and 4 shaft sections.

_images/1000020000000548000001DA8FEF24624A1AB56B.png

1.2. Material properties#

The geometric and material characteristics are listed in the following table.

Material

\(E=2{10}^{11}N/{m}^{2}\)

\(\rho =7800\mathrm{kg}/{m}^{3}\)

\(\nu =0.3\)

Disc

\(\mathrm{D1}\)

\(M=20\mathrm{kg}\)

\({I}_{D}=\mathrm{0,20}\mathrm{kg}{m}^{2}\)

\({I}_{P}=\mathrm{0,40}\mathrm{kg}{m}^{2}\)

\(\mathrm{D2}\)

\(M=17\mathrm{kg}\)

\({I}_{D}=\mathrm{0,17}\mathrm{kg}{m}^{2}\)

\({I}_{P}=\mathrm{0,34}\mathrm{kg}{m}^{2}\)

\(\mathrm{D3}\)

\(M=10\mathrm{kg}\)

\({I}_{D}=\mathrm{0,015}\mathrm{kg}{m}^{2}\)

\({I}_{P}=\mathrm{0,30}\mathrm{kg}{m}^{2}\)

The characteristics of the bearings vary linearly according to the speed of rotation:

  • to \(5000\mathrm{tr}/\mathrm{min}\):

Level

\(\mathrm{P1}\)

\(\mathrm{kyy}=9{10}^{7}N/m\)

\(\mathrm{kzz}=5{10}^{8}N/m\)

\(\mathrm{kyz}=9{10}^{4}N/m\)

\(\mathrm{kzy}=-9{10}^{4}N/m\)

\(\mathrm{cyy}=\mathrm{1,5}{10}^{5}\mathrm{Ns}/m\)

\(\mathrm{czz}=4.5{10}^{5}\mathrm{Ns}/m\)

\(\mathrm{cyz}=-1{10}^{2}\mathrm{Ns}/m\)

\(\mathrm{czy}=1{10}^{2}\mathrm{Ns}/m\)

Level

\(\mathrm{P2}\)

\(\mathrm{kyy}=6{10}^{7}N/m\)

\(\mathrm{kzz}=\mathrm{1,5}{10}^{8}N/m\)

\(\mathrm{kyz}=8{10}^{4}N/m\)

\(\mathrm{kzy}=-8{10}^{4}N/m\)

\(\mathrm{cyy}=\mathrm{1,2}{10}^{5}\mathrm{Ns}/m\)

\(\mathrm{czz}=\mathrm{1,9}{10}^{5}\mathrm{Ns}/m\)

\(\mathrm{cyz}=-1{10}^{2}\mathrm{Ns}/m\)

\(\mathrm{czy}=1{10}^{2}\mathrm{Ns}/m\)

  • to \(6500\mathrm{tr}/\mathrm{min}\):

Level

\(\mathrm{P1}\)

\(\mathrm{kyy}=1{10}^{8}N/m\)

\(\mathrm{kzz}=4{10}^{8}N/m\)

\(\mathrm{kyz}=\mathrm{1,5}{10}^{5}N/m\)

\(\mathrm{kzy}=-\mathrm{1,5}{10}^{5}N/m\)

\(\mathrm{cyy}=\mathrm{1,3}{10}^{5}\mathrm{Ns}/m\)

\(\mathrm{czz}=3.3{10}^{5}\mathrm{Ns}/m\)

\(\mathrm{cyz}=-1{10}^{2}\mathrm{Ns}/m\)

\(\mathrm{czy}=1{10}^{2}\mathrm{Ns}/m\)

Level

P2

\(\mathrm{kyy}=7{10}^{7}N/m\)

\(\mathrm{kzz}=\mathrm{1,4}{10}^{8}N/m\)

\(\mathrm{kyz}=\mathrm{1,3}{10}^{5}N/m\)

\(\mathrm{kzy}=-\mathrm{1,3}{10}^{5}N/m\)

\(\mathrm{cyy}=1{10}^{5}\mathrm{Ns}/m\)

\(\mathrm{czz}=\mathrm{1,5}{10}^{5}\mathrm{Ns}/m\)

\(\mathrm{cyz}=-1{10}^{2}\mathrm{Ns}/m\)

\(\mathrm{czy}=1{10}^{2}\mathrm{Ns}/m\)

1.3. Boundary conditions#

To block rigid body movements in direction \(x\), we block the degree of freedom \(\mathrm{DX}\) at the level node \(\mathrm{B1}\).