2. Benchmark solution

2.1. Calculation method used for the reference solution

Let’s say a quantity \(G\) with 3 components \(X,Y,Z\)

The mesh has 3 geometric entities (meshes or nodes): \(\mathit{X1},\mathit{X2},\mathit{X3}\)

First of all, 2 fields \(\mathit{ch1}\) and \(\mathit{ch2}\) are made by assigning the quantity \(G\) to the geometric entities \(\mathit{X1}\), \(\mathit{X2}\) and \(\mathit{X3}\).

Entity	\(\mathit{X1}\)			\(\mathit{X2}\)			\(\mathit{X3}\)
Component	\(X\)	\(Y\)	\(Z\)	\(X\)	\(Y\)	\(Z\)	\(X\)	\(Y\)	\(Z\)
\(\mathit{ch1}\)
\(\mathit{ch2}\)

Fields \(\mathit{ch3}\) and \(\mathit{ch4}\) are then defined by CREA_CHAMP operation ASSE.

We must then obtain:

Entity	\(\mathit{X1}\)			\(\mathit{X2}\)			\(\mathit{X3}\)
Component	\(X\)	\(Y\)	\(Z\)	\(X\)	\(Y\)	\(Z\)	\(X\)	\(Y\)	\(Z\)
\(\mathit{ch1}\)
\(\mathit{ch2}\)
\(\mathit{ch3}\)
\(\mathit{ch4}\)

To test the different scenarios of the operation “ASSE” of the CREA_CHAMP command, this calculation is done for 5 types of fields:

A	cham_no	trips
B	cham_elem/ELNO	constraints
C	cham_elem/ELGA	constraints
D	cham_elem/ELNO	internal variables
E	cham_elem/ELGA	internal variables

2.2. Benchmark results

For the 5 previous scenarios, we test the values greased and underlined in the table below:

Entity	\(\mathit{X1}\)			\(\mathit{X2}\)			\(\mathit{X3}\)
Component	\(X\)	\(Y\)	\(Z\)	\(X\)	\(Y\)	\(Z\)	\(X\)	\(Y\)	\(Z\)
\(\mathit{ch3}\)				1.			1.	12.	9.
\(\mathit{ch4}\)							18.

2.3. Uncertainties about the solution

No uncertainty.