5. Current function examples

5.1. With data from both groups

Definition of current functions using data from both the first group and the second group.

Case of two-phase short circuit lasting 0.5 seconds with reset of 1.5 to 2 seconds of intensity \(20\mathrm{kA}\), of zero phase and time constant 0.2 seconds before resetting and of intensity \(15\mathrm{kA}\) after resetting.

• Data from the first group:

COUR =( _F (INTE_CC_1 = 20.E3, TAU_CC_1 = 0.2, PHI_CC_1 = 0., INTE_CC_2 = 20.E3, TAU_CC_2 = 0.2, PHI_CC_2 = 180. , INST_CC_INIT = 0., INST_CC_FIN = 0.5, ),

_F (INTE_CC_1 = 15.E3, TAU_CC_1 = 0.2, PHI_CC_1 = 0., INTE_CC_2 = 15.E3, TAU_CC_2 = 0.2, PHI_CC_2 = 180. , INST_CC_INIT = 1.5, INST_CC_FIN = 2.0, ),), )

• Data from the second group:

COUR_PRIN =( _F (INTE_CC_1 = 20.E3, TAU_CC_1 = 0.2, PHI_CC_1 = 0., INTE_RENC_1 = 15.E3, TAU_RENC_1 = 0.2, PHI_RENC_1 = 0. , INST_CC_INIT = 0., INST_CC_FIN = 0.5, INST_RENC_INIT = 1.5, INST_RENC_FIN = 2.0, ),), COUR_SECO = (_F (INTE_CC_2 = 20.E3, TAU_CC_2 = 0.2, PHI_CC_2 = 180., INTE_RENC_2 = 15.E3, TAU_RENC_2 = 0.2, PHI_RENC_2 = 180. , ),), )

5.2. With only data from the first group

Definition of current functions using strict the data from the first group.

Cases of two-phase short circuit lasting 1 second, zero phase, time constant 0.2 second and intensity levels of \(20\mathrm{kA}\) during 0.5 second, \(15\mathrm{kA}\) between 0.5 second and 0.7 second, \(10\mathrm{kA}\) between 0.7 second and 1 second, between 0.7 seconds and 1 second.

COUR =( _F (INTE_CC_1 = 20.E3, TAU_CC_1 = 0.2, PHI_CC_1 = 0., INTE_CC_2 = 20.E3, TAU_CC_2 = 0.2, PHI_CC_2 = 180. , INST_CC_INIT = 0., INST_CC_FIN = 0.5, ),

_F (INTE_CC_1 = 15.E3, TAU_CC_1 = 0.2, PHI_CC_1 = 0., INTE_CC_2 = 15.E3, TAU_CC_2 = 0.2, PHI_CC_2 = 180. , INST_CC_FIN = 0.7, ),

_F (INTE_CC_1 = 10.E3, TAU_CC_1 = 0.2, PHI_CC_1 = 0., INTE_CC_2 = 10.E3, TAU_CC_2 = 0.2, PHI_CC_2 = 180. , INST_CC_FIN = 1.0, ),), )

5.3. Preferably with data from the second group

Definition of current functions using preferential data from the second group.

To express the interaction of two conductors with the phase studied, the use of data from the first group would lead to the definition of two functions F1 and F2 (by two calls to DEFI_FONC_ELEC) and two charges ch1 and ch2.

The data in the second group makes it possible to be limited to a single function.

Case of three-phase short circuit lasting 1 second of intensity 20 kA, phase 45 degrees, time constant 0.2 second with parallel and infinite phases 2 meters apart.

COUR_PRIN =( _F (INTE_CC_1 = 20.E3, TAU_CC_1 = 0.2, PHI_CC_1 = 45., INST_CC_INIT = 0. , INST_CC_FIN = 1. , ),),

COUR_SECO =( _F (INTE_CC_2 = 20.E3, TAU_CC_2 = 0.2, PHI_CC_2 = 165., DIST = 2. , ),

_F (INTE_CC_2 = 20.E3, TAU_CC_2 = 0.2, PHI_CC_2 = - 75., DIST = - 2. , ),), )

Examples of DEFI_FONC_ELEC can be found in test cases SDNL101A, SDLL102A, and SDLL102B.