1. Reference problem#

1.1. Geometry#

According to the modeling \(\mathrm{2D}\) (plane deformation) or \(\mathrm{3D}\), we consider respectively a rectangle or a bar (see Figure 1.1-1).

_images/100002010000025C000001B9E3FEB8F31B7BFF89.png

Figure 1.1-a : Geometry and Meshing of a rectangle (a) and a bar (b)

1.2. Material properties#

Elasticity:

\(E=190000\text{MPa}\)

Young’s module

\(\mathrm{\nu }=0.3\)

Poisson’s ratio

Work hardening curve:

\(R(\mathrm{\kappa })=488.36+57.13(1-\mathrm{exp}(-8613\mathrm{\kappa }))+238.73(1-\mathrm{exp}(-10.39\mathrm{\kappa }))\)

Ductile damage law GTN:

\({q}_{1}=1.5\)

Model parameter GTN

\({q}_{2}=1.07\)

Model parameter GTN

\({f}_{0}=0.0002i\)

Initial porosity

\({f}_{n}=0\)

Germination Parameter

\({f}_{c}=0.05\)

Coalescence porosity

\(\mathrm{\delta }=3\)

Coalescence coefficient related to coalescence

\(c=1N\)

Non-local parameter

\(r=5000\mathit{MPa}\)

Lagrange penalty parameter

In particular, the distribution of the initial porosity is not homogeneous. It increases with altitude: \({f}_{0}=0.0002i\) where \(i\) refers to the i-th element layer and \(1\le i\le 10\).

In DEFI_MATERIAU, the following information should be filled in:

ELAS

ECRO_ NL

GTN

NON_LOCAL

E = 190000

R0= 488.361123569

Q1 = 1.5

C_ GRAD_VARI = 1

NU = 0.3

R1 = 57.1333673502

Q2 = 1.07

PENA_LAGR =5000

GAMMA_1 = 8613

PORO_INIT = 0.0002i

R2 = 238.731127339

COAL_PORO = 0.05

GAMMA_2 =10.386585592

COAL_ACCE = 3

1.3. Boundary conditions and loads#

For modeling \(2D\) (plane deformation), the displacements along the \(X\) axis of all the nodes are controlled: \({u}_{x}=5x\), the displacements along the \(Y\) axis of the nodes of the same altitude remain uniform, the node \(A\) is blocked along the \(Y\) axis (see Figure 1.1-1 (a) for geometry).

For modeling \(3D\), the movements along the \(X\) axis of all the nodes are controlled: \({u}_{x}=5x\), the movements along the \(Y\) axis of all the nodes are blocked, the movements along the \(Z\) axis of the nodes of the same altitude remain uniform, the node \(A\) is blocked according to \(Z\). (see Figure 1.1-1 (b) for geometry).

Boundary conditions and loads are imposed this way so that the problem in \(2D\) and the problem in \(3D\) are the same.

The load is imposed using 1000 identical time steps. The pseudo-calculation time is 1.