Reference problem
=====================


Geometry
---------


.. image:: images/10000000000002800000028D9DF5DADE3F7AC98C.png
    :width: 2.678in
    :height: 2.6472in


.. _RefImage_10000000000002800000028D9DF5DADE3F7AC98C.png:

height: :math:`h\mathrm{=}1m`

width: :math:`l=1m`

thickness: :math:`e=1m`

Coordinates of points (in meters):


.. csv-table::

    "", ":math:`A` "," :math:`B` "," :math:`C` "," :math:`D`"
    ":math:`x` ", "0. ", "0. ", "0.5", "1."
    ":math:`y` ", "0. ", "1. ", "0.5", "1."
    ":math:`z` ", "0. ", "0. ", "0.5", "0."



Material properties for model LETK
----------------------------------------

PA = 0.1

NELAS = 0.

SIGMA_C = 12.

H0_ EXT = 1.10292

GAMMA_CJS = 0.8

XAMS = 0.1

ETA = 0.04

A_0 = 0.25

A_E = 0.60

A_ PIC = 0.4

S_0 = 0.0005

M_0 = 0.01

M_E = 2.

M_ PIC = 6.

M_ ULT = 0.61

XI_ULT = 0.365

XI_E = 0.028

XI_PIC = 0.015

MV_MAX = 3.

XIV_MAX = 0.0039

A = 1.5e-12

N = 4.5

SIGMA_P1 = 57.8

MU0_V = 0.1

XI0_V = 0.3

MU1 = 0.1

XI1 = 0.3


Material properties for model LKR
------------------------

PA = 2.1

GAMMA =.85

M_0 = .5

F_P = 0.136047510046

M_1 = 9.69880017363

SIGMA_C = 10.9985715832

A_2 = 0.580184800258

Q_I = 100.000648048

V_1 = 1.5

V_2 = 1.5

XI_1 = 1.e-2

XI_2 = 1.8e-2

XI_5 = 1.6e-2

A = 1.e-18

N = 3.5

RHO_1 = 1.

RHO_2 = 0.1

RHO_4 = 1.10668567265

R_Q = 0. (except for J models, = 1.e-6)

R_M = 0. (except for J models, = 1.e-6)

R_S = 0. (except for J models, = 1.e-6)

R_X1 = 0. (except for J models, = 1.e-6)

R_X2 = 0. (except for J models, = 1.e-6)

R_X5 = 0. (except for J models, = 1.e-6)

Z = 0. (except for J models, = 1.e-6)

COUPLAGE_P_VP = 1

A_ SIGC = 0.155495602806

B_ SIGC = 4.69721443803


Material properties for model KH_CSRM
--------------------------------------------

Material parameters are given in the International System of Units (SI).

YoungModulus=7.0E9

Fish ratio = 0.3

Isocomplaslim=50.0E6

Isotenselaslim=0.1E6

MCCSlopeCSL =0.5

NLHIndex =1.0

MbigocritCoef=10.0

abigocritCoef=0.75

IncompIndex=15.0

Tau=2.0e2

PerzynaExpo=2.0

NLHModulusP =7.0e9/2.5

NLHModulusV =0.01*7.0e9

Initial conditions, boundary conditions, and loading
-----------------------------

**Phase 1:**

The sample is brought to a homogeneous state: :math:`{\sigma }_{\text{xx}}^{0}\mathrm{=}{\sigma }_{\text{yy}}^{0}\mathrm{=}{\sigma }_{\text{zz}}^{0}`, by imposing the corresponding confinement pressure on the front, right lateral and upper faces. The movements are blocked on the back (:math:`{u}_{x}\mathrm{=}0`), left side (:math:`{u}_{y}\mathrm{=}0`) and bottom (:math:`{u}_{z}\mathrm{=}0`) faces.

**Phase 2:**

The movements are maintained blocked on the rear (:math:`{u}_{x}\mathrm{=}0`), left lateral (:math:`{u}_{y}\mathrm{=}0`) and lower (:math:`{u}_{z}\mathrm{=}0`) faces, as well as the confinement pressure on the front and right lateral faces. An imposed displacement is applied on the upper face: :math:`{u}_{z}(t)`, so as to obtain a deformation :math:`{\epsilon }_{\text{zz}}=-6\text{\%}` over a period of 6e3 seconds for the A, B, C, F, G, H, I and J models and a duration of 6e5 seconds for the D, E, K and L models.

For the I and J models, an increasing temperature is imposed in phases 1 and 2 via the keyword factor AFFE_VARC. The temperature is increased from 0° C. to 50° C. during phase 1 and from 50° C. to 100° C. during phase 2.

For modeling M, the deformation at the end of the test is a hundred times greater than that obtained at the end of the confinement phase: -0.00028571428571428574* 100.