2. Benchmark solution#
2.1. Calculation method used for the reference solution#
The problem is solved analytically.
The result of the efforts (equal to the total weight) is equal to:
concrete weight: \(\mathrm{Pb}=V{\rho }_{b}g\)
cable weight: \(\mathrm{Pc}=AL{\rho }_{c}g\)
in the direction in which gravity is applied.
The structure is isostatic. Prestressing forces are self-balanced.
Let \({S}_{b}\) be the area of the concrete in a plane perpendicular to the cable \({S}_{b}=(2\times \mathrm{0,6}){m}^{2}\), \({E}_{a}\) and \({E}_{b}\) the modules of steel and concrete, \({N}_{a}\) the tension in the cable and \({\sigma }_{b}\) and the stress in the concrete after tension.
The balance of the concrete and cable assembly is written: \({N}_{a}+{\sigma }_{b}{S}_{b}\mathrm{=}0\) therefore \({\sigma }_{b}\mathrm{=}\mathrm{-}\frac{{N}_{a}}{{S}_{b}}\)
Since the macro command CALC_PRECONT is used, and since there is no friction or losses in the cable, the tension in the cable is equal to the initial tension, unlike the case where RELA_CINE_BP is used, which suffers prestress losses due to the shortening of the concrete (see test SSNP108, [V6.03.108])
The deformation of concrete is: \({\varepsilon }_{b}=\frac{{\sigma }_{b}}{{E}_{b}}\)
2.2. Benchmark results#
Result of efforts: \(R=132N\)
Stress in concrete: \({\sigma }_{b}\mathrm{=}\mathrm{-}\mathrm{1,66666667}{10}^{5}\mathit{Pa}\)
Normal force in steel: \({N}_{a}\mathrm{=}2{10}^{5}\mathit{Pa}\)
Deformation in concrete: \({\varepsilon }_{b}=-\mathrm{5,555555555}{10}^{\text{-}6}\)
2.3. Uncertainty about the solution#
It is an analytical solution.
The solution gives the average stress in concrete. When there are several elements (models \(B\) and \(C\)) it is necessary to average the values of the cells.