Reference problem
=====================


Geometry
---------


.. image:: images/10000201000003AE0000054EEC0940F4241A08AB.png
    :width: 2.0646in
    :height: 2.9772in


.. _RefImage_10000201000003AE0000054EEC0940F4241A08AB.png:

**Figure** 1.1-a **: geometry of the cracked plate**

Geometric dimensions of the cracked plate:


.. csv-table::

    "width", ":math:`L=1000\mathrm{mm}`"
    "height", ":math:`H=2000\mathrm{mm}`"


Initial crack length: :math:`{a}_{0}=300\mathrm{mm}`.

The cracks are positioned in the middle of the height of the plate (:math:`H/2`).


Material properties
----------------------

Young's module :math:`E=206000\mathrm{MPa}`

Poisson's Ratio :math:`\nu =0.33`


Boundary conditions and loads
-------------------------------------


.. image:: images/1000020100000366000005D0C35114DB74F36B79.png
    :width: 2.189in
    :height: 3.7429in


.. _RefImage_1000020100000366000005D0C35114DB74F36B79.png:

**Figure** 1.3-a **: boundary conditions and loads**

Boundary conditions:

 Point :math:`A`: :math:`\Delta X\mathrm{=}\Delta Y\mathrm{=}0`

 Points on the lower end of the plate: :math:`\Delta Y\mathrm{=}0`

Loading:

 Pressure applied to the upper end of the plate: :math:`P\mathrm{=}1\mathit{MPa}`

Three propagations are calculated by imposing a maximum crack advance equal to :math:`30\mathit{mm}`. As a result of the symmetry of the geometry, the boundary conditions and the loading, the advances of the two cracks are always equal to the maximum advance imposed.