Reference problem
=====================


Geometry
---------


.. image:: images/10000201000003B200000568F53E16703F22447C.png
    :width: 2.1575in
    :height: 3.1563in


.. _RefImage_10000201000003B200000568F53E16703F22447C.png:

**Figure** 1.1-a **: geometry of the cracked plate**

Geometric dimensions of the cracked plate:


.. csv-table::

    "width", ":math:`L=1000\mathrm{mm}`"
    "height", ":math:`H=2000\mathrm{mm}`"


Initial crack length: :math:`{\mathrm{2a}}_{0}=300\mathrm{mm}`.

The crack is positioned in the middle of the height of the plate (:math:`H/2`).


Material properties
----------------------

Young's module :math:`E=206000\mathrm{MPa}`

Poisson's ratio :math:`\nu =0.33`


Boundary conditions and loads
-------------------------------------


.. image:: images/1000020100000356000005BE59586ECB652D94DC.png
    :width: 2.0425in
    :height: 3.5154in


.. _RefImage_1000020100000356000005BE59586ECB652D94DC.png:

**Figure** 1.3-a **: boundary conditions and loads**

Boundary conditions:

 Point :math:`A`: :math:`\Delta X=\Delta Y=0`

 Lower end of plate points: :math:`\Delta Y=0`

Loading:

 Pressure applied to the upper end of the plate: :math:`P=1\mathrm{MPa}`

Three propagations are calculated by imposing a crack advance equal to :math:`30\mathrm{mm}` at each crack bottom. As a result of the symmetry of the geometry, the boundary conditions and the loading, the advances of the two bottoms of the crack are always equal to the imposed advance.